SFX Question

[+atari2600land]

Suppose I got this code (I snipped it from a game I'm working on). When a{2}=1 (or when the player falls), f automatically goes to 7 instead of being 1 like it should be. Why?

 

 
if a{1} then t=t+1 : y=y-1 : n=n-1 : b=3 : f=f-1
if a{1} && f<2 then f=1
if t=40 then a{1}=0 : a{2}=1

if a{2} then y=y+1 : n=n+1 : b=3 : f=f+1
if a{2} && f>7 then f=7

Edited May 12, 2007 by atari2600land

[SeaGtGruff]

Suppose I got this code (I snipped it from a game I'm working on). When a{2}=1 (or when the player falls), f automatically goes to 7 instead of being 1 like it should be. Why?

 

 
if a{1} then t=t+1 : y=y-1 : n=n-1 : b=3 : f=f-1
if a{1} && f<2 then f=1
if t=40 then a{1}=0 : a{2}=1

if a{2} then y=y+1 : n=n+1 : b=3 : f=f+1
if a{2} && f>7 then f=7

If this code is part of a loop, then whenever a{2} is 1, the next-to-last line will keep incrementing f each time through the loop, and the last line will prevent f from exceeding 7-- so after you go through the loop a few times, f will be 7.

 

Michael