More Noobie Questions about bB

[+Living Room Arcade]

Combining Unused Bits into a Byte

 

Got a noobie question for you guys.  Can anyone help me with this?  So, I've been working with bB for a couple of months now, and sometimes in my programs I find that I have a few unused bits, all from different memory locations in RAM.  So what I'm wondering is, is there any way to combine eight of those unused bits into a single byte that I can read from and write to just like an ordinary a-z byte of RAM?  Any help is appreciated.  Thank you.  

[+Random Terrain]

Are you talking about using bits for different jobs like this?

 

   dim _Bit0_Hero_Shot = a
   dim _Bit1_Hero_Thrust = a
   dim _Bit2_Hero_Crash = a
   dim _Bit3_Hero_Shield = a
   dim _Bit4_Enemy_Shot = a
   dim _Bit5_Enemy_Thrust = a
   dim _Bit6_Enemy_Crash = a
   dim _Bit7_Enemy_Shield = a

 

 

If so, and you are using bits in a few different variables, you could just carefully rename them and move them into one variable instead of being spread out.

 

But I could be misunderstanding your question.

[+Living Room Arcade]

Hey, @Random Terrain.  It's a real pleasure to be messaging with you here in the forum.  Do you know I've been using your online bB Guide for the last few months?  What a treasure trove of info about bB you've put together there.  I want to thank you for doing that.  It's truly a treasure.

 

About my question - no, that's not my meaning.  My meaning is sort of like the reverse.  Suppose the following bits are free: a{8}, b{8}, c{8}, d{8}, e{8}, f{8}, g{8} and h{8}.  Could these eight, separate bits be combined, somehow, into a single byte?  See what I'm saying?  What do you think?  

[+Random Terrain]

From what I understand, bits are from 0 to 7, so something like a{8} shouldn't be valid. Seems like a{7} would be what you mean.

 

As far as I know, what you are asking is not possible. If you would be using 0 through 6 of the bits individually in each variable, you could move them so b{0} would be moved to a{7} and keep moving everything until you end up with h as a free variable.

[+Living Room Arcade]

@Random Terrain 

Quote

Seems like a{7} would be what you mean.

Yes, that's what I meant.  

Quote

As far as I know, what you are asking is not possible. If you would be using 0 through 6 of the bits individually in each variable, you could move them so b{0} would be moved to a{7} and keep moving everything until you end up with h as a free variable.

I see.  Alright.  Thanks, RT.